Question

Find the sides of the ∆ AOB in the following figure where the side of the sq. is 4m. [Angle O is the point of intersection of Diagonals]​

Answer 1

Answer:

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Answer 2

Answer:

4m, 2√2m, 2√2m.

Step-by-step explanation:

Let the square be ABCD. So, AC and BD are diagonals. Diagonals of square are equal in length.

So, AC=BD.

Diagonals of square are perpendicular to each other and bisect each other.

Let the diagonals intersect at O.

So, angle AOB=90°.

And, AO=BO.

Applying the Pythagoras theorem,

AB²=AO² + BO²

(4m)²=2 * AO²

16m²=2 * AO²

AO²=16m²/2

AO²=8m²

AO=2√2m

As AO=BO,

AO=BO=2√2m

So, sides of ΔAOB are 4m, 2√2m and 2√2m.