Question

find the sides of the squares ​

Answer 1

Answer:

im

Step-by-step explanation:

sum of area of the 2 square is 468m^2

the difference between perimeter is 24m

so, 4a -4A is 24

4[A-a] is 24

A-a is 6m

sum of area is 468

ie,

a^2+A^2 is 468

a+A is $\sqrt[4]{468}$

a+A is 4.6

A+a + A- a is 24-46

4.40