Question

find the sides of the triangle by the sides x=0,x+2y=5,3x-y=1​

Answer 1

Answer:

Slope of line 4x+3y=5 is

3

−4

and Slope of line 3x−4y=0 is

4

3

Product of their Slopes is

4

3

∗

3

−4

=−1

Hence, The line 3x−4y=0 is Perpendicular to side 4x+3y=5

And Orthocentre is the intersection of Perpendiculars

So, the line 3x−4y=0 must have passed through the Orthocentre of the triangle

Step-by-step explanation:

hope this will help u