Math, asked by akankshazin, 10 months ago

Find the sides of the triangle whose perpendicular sides are in ratio 5:12 with the perimeter 120.

Answers

Answered by umangdubey264
1

Answer:

120=5x+12x=180

Step-by-step explanation:

120=17x=180

120=10.58

0.008

Answered by Anonymous
10

Let, the common multiple of the ratio be, 'x'

So, the perpendicular sides are_

(5*x)

= 5x

(12*x)

= 12x

∴ The third side(hypotenuse) of the triangle is_

√{(5x)²+(12x)²}

=√(25x²+144x²)

= √(169x²)

= 13x

According to the given condition,

5x + 12x + 13x = 120

⇒ 30x = 120

⇒ x = 120/30

⇒ x = 4

∴ The sides of the triangle are_

(5*4)

= 20

(12*4)

= 48

(13*4)

= 52

So, the sides are 20 units, 48 units and 52 units.

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