Find the sides of the triangle whose perpendicular sides are in ratio 5:12 with the perimeter 120.
Answers
Answered by
1
Answer:
120=5x+12x=180
Step-by-step explanation:
120=17x=180
120=10.58
0.008
Answered by
10
Let, the common multiple of the ratio be, 'x'
So, the perpendicular sides are_
(5*x)
= 5x
(12*x)
= 12x
∴ The third side(hypotenuse) of the triangle is_
√{(5x)²+(12x)²}
=√(25x²+144x²)
= √(169x²)
= 13x
According to the given condition,
5x + 12x + 13x = 120
⇒ 30x = 120
⇒ x = 120/30
⇒ x = 4
∴ The sides of the triangle are_
(5*4)
= 20
(12*4)
= 48
(13*4)
= 52
So, the sides are 20 units, 48 units and 52 units.
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