Question

find the simple interest and amount to be paid at the end of 4 year if principal = rupees 2000 at 1fast

​

Answer 1

Answer:

80

Step-by-step explanation:

p =2000

time =4

rate =1

si =p*r*t/100

2000*4*1/100

80

Answer 2

Given :

P(principal) = ₹2,000

r(rate) = 12%

n(time) = 4 years.

To find :

The simple interest after 4 years by following the given situations.

Solution :

We know that :

${ \underline{ \boxed{ \bf {S. I. = \frac{p \times r \times t}{100}}}}}$

Substituting the given values as follows :

$\sf \longrightarrow S. I. = \frac{p \times r \times t}{100}$

$\sf \longrightarrow S. I. = \frac{20 \cancel{00} \times 12 \times 4}{1 \cancel{00}}$

$\sf \longrightarrow S. I. = 20 \times 12 \times 4$

$\sf \longrightarrow S. I. = ₹960$

Required answer :

Simple interest to added after 4 years is ₹960