Question

Find the simple interest and the among of simple interest rs350 for 4years at 6% p.a.

Answer 1

p×r×t/100
p=350
r=6
t=4
350×4×6/100
ans 84

Answer 2

CORRECT QUESTION :

Find the simple interest and the amount of principal rs350 for 4years at 6% p.a.

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=84\:rupees}}}$

$\green{\therefore{\text{Amount=434\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 4\:years} \\ \\ : \implies \text{Principal(p) = 350\:rupees} \\ \\ : \implies \text{Rate(r) = 6\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{350 \times 6\times4}{100} \\ \\ : \implies S.I = \frac{35 \times24 }{10 } \\ \\ \green{ : \implies \text{S.I= 84\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =180\: rupees}} \\ \\ :\implies Amount=S.I+principal\\\\ \green{:\implies\text{Amount=84+350=434\:rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$