Question

Find the simple interest and the amount when principal =Rs1500,rate=12%p.a. and time =4years 3months

Answer 1

simple interest = p×r×t/100

1500×12×51months/100 (4×12+3 months)

Rs 9,180

(p= principal r= rate t= time)

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=765\:rupees}}}$

$\green{\therefore{\text{Amount=2265\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 4.25\:years} \\ \\ : \implies \text{Principal(p) = 1500\:rupees} \\ \\ : \implies \text{Rate(r) = 12\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{1500 \times 12\times4.25}{100} \\ \\ : \implies S.I = \frac{1500\times51 }{100 } \\ \\ \green{ : \implies \text{S.I= 765\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =765\: rupees}} \\ \\ :\implies Amount=S.I+principal\\\\ \green{:\implies\text{Amount=765+1500=2265\:rupees}} \\\\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$