find the simple interest at the end of one year for the following: c ₹ 2,500 at 9/2% interest per annum
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Answered by
0
Given P=Rs.2,500,r=4%, N=2
CI=P(1+
100
R
)
2
−P=2,500(1+
100
4
)
2
−2,500=2,500(
100
2
104
2
−1)=
10,000
2,500×816
=Rs.204
SI=
100
P×T×R
=
100
2,500×4×2
=Rs.200
Difference=Rs.4
Answered by
4
Answer:
Principle = 2500
Rate of interest = 9/2 %
Time = 1 year
SI = 2500 * 9 * 1/ 100 * 2
= 2500 * 9 / 200
= 25 * 9 / 2
= 225/2
= 112.5
Step-by-step explanation:
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