Question

find the simple interest earn(I) 8000 at 12percent for 3 years (ii). 525 at 5 and d half percent for 1year​

Answer 1

$\large\sf\underline{Question\:1\::}$

• Find the Simple Interest ( SI ) when Principal = Rs 8000 , Rate = 12 % and Time = 3yrs

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$\large\sf\underline{Solution\::}$

We know,

$\small{\underline{\boxed{\mathrm\pink{SI\:=\:\frac{Principal \times Rate \times T}{100}}}}}$

• Substituting the given values :

$\sf\:SI\:=\:\frac{8000 \times 12 \times 3}{100}$

$\sf\implies\:SI\:=\:\frac{8000 \times 36}{100}$

$\sf\implies\:SI\:=\:\frac{288000}{100}$

$\sf\implies\:SI\:=\:\frac{2880\cancel{00}}{1\cancel{00}}$

$\large{\mathfrak\red{\implies\:SI\:=\:Rs\:2880}}$

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$\large\sf\underline{Question\:2\::}$

• Find the Simple Interest ( SI ) when Principal = Rs 525 , Rate = $\sf\:5\frac{1}{2}$% and Time = 1yrs

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$\large\sf\underline{Solution\::}$

We know,

$\small{\underline{\boxed{\mathrm\pink{SI\:=\:\frac{Principal \times Rate \times T}{100}}}}}$

Substituting the given values :

$\sf\:SI\:=\:\frac{525 \times 5\frac{1}{2} \times 1}{100}$

$\sf\implies\:SI\:=\:\frac{525 \times \frac{11}{2} \times 1}{100}$

$\sf\implies\:SI\:=\:\frac{525 \times \frac{11}{2}}{100}$

$\sf\implies\:SI\:=\:\frac{\frac{5775}{2}}{100}$

$\sf\implies\:SI\:=\:\frac{5775}{2} \times \frac{1}{100}$

$\sf\implies\:SI\:=\:\cancel{\frac{5775}{200}}$

$\sf\implies\:SI\:=\:\cancel{\frac{1155}{40}} = \frac{231}{8}$

$\large{\mathfrak\red{\implies\:SI\:=\:Rs\:28.875}}$

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!! Hope it helps;!!