Question

find the simple interest if,
principal = 4500
rate = 6 1/4 %
time = 9 months

Answer 1

ʜᴇy ᴛʜᴇʀᴇ ✌✌

ᴜʀ ᴀɴꜱ ɪꜱ ʜᴇʀᴇ

ɪɴᴛᴇʀᴇꜱᴛ =Interest is the price paid by a borrower for the use of a lender's money.

TYPE OF INTEREST----- there are 2 type of interest--
●Simple Interest
●Compound Interest

♥Simple Interest = Simple interest is the computed on the principal for the entire period of borrowing.
Formula -----
I = Pit
A = P + I
I = A - P

here
I = Amount of Interest
P = principal ( initial value of an investment)
A = Accumulated amount ( Final value of an investment)
i = Annual interest rate in decimal
t = time in years

♥Compound Interest = compound interest as the interest that accrues when earnings for each specified period of time added to the principal thus increasing the principal base on which subsequent interest is compound.

Formula -
A = p (1 + i)^n
where,
i = Annual rate of interest
n = Number of conversion period per year
INTEREST = An - P
or
= P ( 1 + i)^n - P

Let, move to ur Question -----

1.
ɢɪᴠᴇɴ -
ᴩ = ₹4500
ᴛɪᴍᴇ =9 ᴍᴏɴᴛʜꜱ
ʀᴀᴛᴇ = 6 1/4 % ᴏʀ 6.25

We know that -
ꜱɪᴍᴩʟᴇ ɪɴᴛᴇʀᴇꜱᴛ = ᴩʀᴛ/100
= 4500× 6.25 × 9 /100 ×12
=₹ 210.93


2. ɢɪᴠᴇɴ -
ᴩ =₹ 8250
ʀᴀᴛᴇ = 9%
ᴛɪᴍᴇ = 18 ᴍᴏɴᴛʜꜱ

we know that -
ꜱɪᴍᴩʟᴇ ɪɴᴛᴇʀᴇꜱᴛ= ᴩʀᴛ/100

so ,
SI =8250× 9 ×18/100×12
=₹ 1113.75
̲
hσpє ít hєlpѕ u ☺☺
fєєl frєє tσ αѕk αnч quєrч❤❤

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=210.93\:rupees}}}$

$\green{\therefore{\text{Simple\:interest=1113.75\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 9\: month} \\ \\ : \implies \text{Principal(p) = 4,500\:rupees} \\ \\ : \implies \text{Rate(r) = 6.25\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{4,500 \times 6.25 \times\frac{9}{12} }{100} \\ \\ : \implies S.I = \frac{4,500 \times 56.25}{12\times 100 } \\ \\ \green{ : \implies \text{S.I= 210.93\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =210.93\: rupees}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 18\: month} \\ \\ : \implies \text{Principal(p) = 8250\:rupees} \\ \\ : \implies \text{Rate(r) = 9\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{8250\times 9 \times\frac{18}{12} }{100} \\ \\ : \implies S.I = \frac{825 \times 162}{12\times 10 } \\ \\ \green{ : \implies \text{S.I= 1113.75\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =1113.75\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$