Math, asked by sonalipagare898, 1 month ago

) Find the simple interest of 1000 kept for 2 years at 3 % rate of interest.

2) Find the amount and interest of 5000 kept for 2 years at 7 % rate of interest​

Answers

Answered by vimaljegim
0

Answer:

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Step-by-step explanation:

1

st

year

Principal, P=Rs.5000

Time, T=1 year

Rate of interest ,R=6%

∴simple Interest, SI=

100

PTR

=

100

5000×10×6

=Rs.300

∴Amount=P+SI=Rs.5300

2nd year

Principal = Amount of 1st year=Rs.5300

Rate of interest =8%

Time =1 year

∴ Interest =

100

5300×1×8

=Rs.424

∴ Amount =Rs.(5300+424)=Rs.5724

The interest of 2nd year is the required compound interest. So, C.I=rs.424 and the required amount is Rs.5724

Answered by JigyashaJain
2

Step-by-step explanation:

Simple Interest = (P × R × T)/100

1. P = 1000, R = 3% , T = 2yr

S.I. = (1000×3×2)/100

= 6000/100

= 60

2. P = 5000, R = 7%, T = 2y

S.I. = (5000×7×2)/100

= 70000/100

= 700

Amount = Principal Amount + S.I.

= 5000 + 700

= 5700

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