Question

find the simple interest of rupees 88000 at 16 whole by 2 by 3 per annum for 9 month​

Answer 1

Given :-

Principal = ₹88,000

Rate = $\bf{{16}}$$\bf\dfrac{2}{3}$%$\bf{{ p.a.}}$

To Find :-

• Simple Interest

Formula, which we will use :-

S.I. = $\bf\dfrac{P\times R\times T}{100}$

Solution :-

Rate = $\bf{{16}}$$\bf\dfrac{2}{3}$%$\bf{{ p.a.}}$

Let us change mixed fraction into improper fraction.

=$\bf\dfrac{50}{3}$%$\bf{{ p.a.}}$

Time = 9 months

Let us change months into years.

= $\bf\dfrac{9}{12}$(1 year = 12 months)

= $\bf\dfrac{3}{4}$years

S.I. = $\bf\dfrac{88000\times 50\times 3}{100\times 3\times 4}$

= $\bf{{11000}}$

$\therefore \bf{{Simple}}$$\bf{{Interest=Rs. 11,000}}$

★ Note :- P denotes for Principal, R denotes for Rate, T denotes for Time and S.I. denotes for Simple Interest.

★___________________________★

Some More Formulas:

• Principal = $\bf\dfrac{Interest\times 100}{Rate\times Time}$

• Rate = $\bf\dfrac{Interest\times 100}{Principal\times Time}$

• Time = $\bf\dfrac{Interest\times 100}{Principal\times Rate}$

★___________________________★