find the simple interest of rupees12500 at the rate of 2½per month for 1½ year
Answers
Answer:
P=Rs.12500
R=12% per annum and T=3 years, then
SI=
100
P×R×T
=Rs.(
100
12500×12×3
)=Rs.4500
In case of Radha:
Amount=P(1+
100
R
)
T
Amount=Rs.[12500×(1+
100
10
)
3
]
=Rs.(12500×
100
110
×
100
110
×
100
110
)=Rs.16637.50
∴ Compound Interest =Rs.(16637.50−12500)=Rs.4137.50
Hence, Fabina pays Rs.(4500−4137.50),i.e.,Rs.362.50 more as interest.
Step-by-step explanation:
Answer:
P=Rs.12500
R=12% per annum and T=3 years, then
SI=
100
P×R×T
=Rs.(
100
12500×12×3
)=Rs.4500
In case of Radha:
Amount=P(1+
100
R
)
T
Amount=Rs.[12500×(1+
100
10
)
3
]
=Rs.(12500×
100
110
×
100
110
×
100
110
)=Rs.16637.50
∴ Compound Interest =Rs.(16637.50−12500)=Rs.4137.50
Hence, Fabina pays Rs.(4500−4137.50),i.e.,Rs.362.50 more as interest.