Math, asked by vijayparth07, 3 months ago


Find the simple interest on 1,680 deposited for one year. The rate of interest fluctuating as
in the beginning of the year 32%, on 1st March fell to 3%, on ist May to 2%, an Ist July rise
to 45. on 1st October fell to 3% and on 1st November fell to 3% and remained so till the end
of the year
Ans. 57.04

Answers

Answered by ajit9835007674
4

Step-by-step explanation:

57.04 is the answer of this question


asthakante: R = 3.395
Answered by singhprathu1
0

Answer:

57.04

Step-by-step explanation:

try using the formula p*r*t

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