Question

Find the simple interest on 1000 in 3 years and 8
months at the rate 6% per annum-​

Answer 1

Answer:

525

Step-by-step explanation:

Let the sum be Rs. z. Then,

S.I. = Rs. (504 - z)

therefore (z x 5 x 4⁄100) = 504 - z

20z = 50400 - 100z

120z = 50400

z = 420

Now P = 420, R = 10%, T = 5⁄2

S.I. = (420 x 10 x 5⁄100 x 2) = 105

Amount = Rs (420 + 105) = 525

Answer 2

Answer:

40 is the simple interest.

Step-by-step explanation:

Given:

⇒ Principal (P) = 1000

⇒ Rate % (R%) = 6%

⇒Time (T) = 8 months

First we need to convert 8 months into Years.

1 year = 12 months

8 months = $\frac{8}{12} = \frac{2}{3}$ months

Now-

⇒ Principal (P) = 1000

⇒ Rate % (R%) = 6%

⇒Time (T) = $\frac{2}{3}$ months

Asked:

Simple Interest = ?

Resolution:

Simple Interest = $\frac{PRT}{100}$

= $\frac{1000*6*2}{100*3}$

= 10 × 2 × 2

= 40

Therefore, 40 is the simple interest on 1000 in 3 years and 8

months at the rate 6% per annum.