Question

find the simple interest on 3000 at 16% per on for the paid from 4th February 2010 to 16th June 2010​

Answer 1

AnswEr :

we will calculate the time of Interest, 2010 was normal year that's why there will be 28 days in February, Now :

⇝ Total Time of Interest

⇝ Feb. + March + April + May + June

⇝ (28 - 4) + 31 + 30 + 31 + 16

⇝ 24 + 108

⇝ 132 Days

• changing it into Year

⇝ $\sf \dfrac{132}{365}\:Year$

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$\bold{Given} \begin{cases}\sf{Principal=Rs. 3000}\\\sf{Rate=16\%\: p.a.}\\\sf{Time= \dfrac{132}{365}\:Yr.}\end{cases}$

• we will calculate Simple Interest Now :

$\leadsto \sf Simple \: Interest= \dfrac{PRT}{100}$

$\leadsto \sf Simple \: Interest= \dfrac{30\cancel{00} \times 16 \times 132}{ \cancel{100}\times 365}$

$\leadsto \sf Simple \: Interest= \dfrac{30 \times 16 \times 132}{365}$

$\leadsto \sf Simple \: Interest=Rs. \: 173.58$

$\leadsto \fbox{\sf Simple \: Interest=Rs. \: 174}$

⠀

∴ There will be Interst of Rs. 174 on sum.

Answer 2

Question :----

• we have to find simple interest ?

Given :----

• Principal = 3000
• Rate = 16%
• Time = 4th feb 2010 to 16th june 2010

Solution :----

First we have to calculate time :----

2010 is a simple year, that means february has = 28 days .

so ,

Total time = 24(feb) + 31(march) + 30(April) + 31(may) + 16(june) = 132 days .

in one simple year = 365 days .

so , time in years will be =( 132/365 ) years ..

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Now we know that,

$SI = \frac{p \times r \times t}{100} \\ \\ putting \: values \\ \\SI = \frac{3000 \times 16 \times 132}{100 \times 365} = 173.58$

⛬ we get, Rs. 173.58 Simple interest after given time .

(Hope it helps you)