Question

Find the simple interest on 4000 at 7.5% p.a. for 3 years and 3 months .also find the amount

Answer 1

$\large \green{ \underline{answer}} \\ \\ \large \implies{3025 \: rupees} \\ \\ \large \implies \orange{ \underline{step \: . \: by \: . \: step \: . \: explanation \: }} \\ \\ \large \implies { \underline{given}} \\ \\ \large \implies{principal \: = \: 4000 \: rs } \\ \\ \large \implies{time \: = \: 3 \: years \: \: 3 \: months} \\ \\ \large \implies{3 \: + \: \frac{3}{12} = \frac{13}{4}years } \\ \\ \large \implies{rate \: = 7.5\% \: pa} \\ \\ \large \implies \blue{ \underline{formula \: \: of \: \: simple \: \: intrest}} \\ \\ \large \implies{ \boxed{S \: . \: I\: = \frac{p \: \times \: r \: \times \: t}{100} }} \\ \\ \large \implies{ \frac{4000 \: \times \: 7.5 \: \times \frac{13}{4} }{100} } \\ \\ \large \implies{S \: . \: I \: = \: 975 \: rs} \\ \\ \large \implies{amount \: \: = \: (P \: - \: S. I)} \\ \\ \large \implies{4000 \: - \: 975} \\ \\ \large \implies{ \boxed{3025 \: rupees \: }}$

Answer 2

Here,

Principal (P) = Rs 4000

Rate of interest (R) = 7.5% p.a.

= (15 / 2) % p.a.

Time (T) = 3 years 3 months

Hence,

Simple Interest (I) = (P × R × T) / 100

= Rs {4000 × (15 / 2) × (13 / 4)} / 100

= Rs (4000 × 15 × 13) / (100 × 2 × 4)

On simplification, we get,

= Rs 5 × 15 × 13

= Rs 975

Therefore,

Amount = P + I

= Rs 14000 + Rs 975

= RS 14, 975

${\fcolorbox{blue}{black}{\orange{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: DecentMortal\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}$