Question

Find the simple interest on ₹6000 at 7% p.a for 10 months

Answer 1

$\underline{\textbf{Given:}}$

$\textsf{Principal=Rs.6000}$

$\mathsf{Rate\,of\,interest=7\%}$

$\mathsf{Time=10\;months=\dfrac{10}{12}\;years}$

$\underline{\textbf{To find:}}$

$\textsf{Simple interest}$

$\underline{\textbf{Solution:}}$

$\underline{\textsf{Simple interest formula:}}$

$\boxed{\mathsf{Simple\;interest=\dfrac{P\,n\,r}{100}}}$

$\implies\mathsf{Simple\;interest=\dfrac{6000{\times}\dfrac{10}{12}{\times}7}{100}}$

$\implies\mathsf{Simple\;interest=60{\times}\dfrac{10}{12}{\times}7}$

$\implies\mathsf{Simple\;interest=5{\times}10{\times}7}$

$\implies\boxed{\mathsf{Simple\;interest=Rs.350}}$

$\underline{\textbf{Find more:}}$

What sum will amount to rs 9520 at 9% pa in 4 years at simple interest?

https://brainly.in/question/15009640

       

Answer 2

Given: Principal(P) = ₹6000, Rate of interest(R)= 7%, Time(T)=10 months

To find The simple interest

Solution: The measure of a specific principal amount of money at some rate of interest for a fixed time, is known as simple interest.

We know that Simple Interest(S.I.)= (Principal(P)×Time(T)×Rate(R)/100

Now as T should be in years,

∴ We know that 12 months=1 year

                        ⇒1 month=1/12 year

                        ∴ 10 months =10/12 years

                                             =5/6 years

∴ S.I.= (P×T×R)/100

⇒S.I.= ₹(6000×(5/6)×7)/100  [substituting the values of P, T, R]

⇒S.I.= ₹(1000×5×7)/100   [dividing 6000/6]

⇒S.I= ₹(100×5×7)

⇒S.I=₹350

Hence the simple interest is ₹350.