Question

Find the Simple Interest on ₹6240 at 6⅔% p.a for a period from December 28, 2011 to May 22, 2012​
plz answer fst ❤❤

Answer 1

Answer:

28th December2011 to 22th May 2012=175 days.

here, P=6240, R=20/3%, T=175/375 year

SI=

\frac{prt}{100}

100

prt

\frac{6240 \times 20 \times 175}{3 \times 100 \times 365}

3×100×365

6240×20×175

=194.14

and the amount is (6240+194.14)=6434.14

Answer 2

$SI = \frac{P×R×T}{100}$

$Principal = 6,240$

$Rate = 6\frac{2}{3} = \frac{20}{3}$

$Time = 147 \: days \: or \: 21 \: weeks$

$SI = \frac{6240 \times 20 \times 21}{3 \times 100}$

$SI =624 \times 2 \times 7$

$SI = 624 \times 14$

$SI = 8,736$