Math, asked by ABCD2056, 1 year ago

Find the simple interest on:
(a) $ 2 LAKH for 5 months 10 DAYS at 1% per MONTH . Find the amount also.

Answers

Answered by Anonymous
23

Formula for S.I

\boxed{\bf{S.I=\frac{P\times R\times T}{100}}}

Here : P = Principal Amount .

R = Rate of interest .

T = Time .

Given :

Principal = $ 2 lakhs .

Time = 5 months 10 days .

Rate = 1 % per month .

1 month = 30 days .

30 days implies 1 month .

1 day implies 1/30 months .

10 days implies 1/3 month ,

5 month + 10 days

= 5 + 1/3 months

= ( 15 + 1 )/3 months

= 16/3 months

\bf{S.I=\dfrac{2\times \frac{16}{3}\times 1}{100}}\\\\\implies \bf{S.I=\dfrac{16}{150}}\\\\\implies \bf{S.I=\dfrac{8}{75}}\\\\\implies \bf{S.I=0.1067} .

\mathbb{INTEREST}

The simple interest is 0.1067 lakhs .

Amount = S.I + P.

S.I was found to be 0.1067 lakhs .

P is given 2 lakhs .

⇒ Amount = 2 lakhs + 0.1067 lakhs

⇒ Amount = $ 2.1067 lakhs .

\mathbb{AMOUNT}

The amount is $ 0.1067 lakhs .

Answered by Anonymous
10

\mathfrak{Answer:}

Amount = $210666.67 & SI = $10666.67.

\mathfrak{Step-by-Step\;Explanation:}

\underline{\underline{\bold{Given\;in\;the\;Question:}}}

Principle = $ 2 lakh.

Rate = 1 % per month.

Time = 5 months and 10 days.

\boxed{\bold{1\;Month=30\;Days.}}\\\\\\\tt{=5+\dfrac{10}{30}}\\\\\\\tt{=5+\dfrac{1}{3}}\\\\\\\tt{=\dfrac{16}{3}\;months.}\\\\\\\\\boxed{\bold{SI=\dfrac{Principle\times Rate\times Time}{100}}}\\\\\\\tt{=\dfrac{200000\times 1\times\dfrac{16}{3}}{100}}\\\\\\\tt{=\dfrac{200000\times 16}{300}}\\\\\\\tt{=\dfrac{32000}{3}}\\\\\\\tt{=\$\;10666.67.}\\\\\\\\

\boxed{\boxed{\bold{Simple\;Interest=\$\;10666.67.}}}\\\\\\\\\boxed{\bold{Amount=Principle+SI}}\\\\\\\tt{=\$\;200000+\$\;10666.67}\\\\\\\tt{=\$\;210666.67.}\\\\\\\\\boxed{\boxed{\bold{Amount=\$\;210666.67.}}}

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