Question

Find the simple interest on a sum of rupees 8250 for 3 years at the rate of 8% per annum

Answer 1

Given :

• Principal,P = Rs. 8250

• Time, T = 3 years

• Rate, R = 8 % p.a.

To find out:

Find the simple interest?

Formula used:

$\sf{S.I = \frac{P \times R \times T}{100} }$

Solution:

$S.I = \frac{P \times R \times T}{100}$

$= \frac{8250 \times 3 \times 8}{100}$

$= \frac{8250 \times 24}{100}$

$= \frac{1980 \cancel{00}}{ \cancel{100} }$

= 1980

Hence, The simple interest is 1980.

Extra information:

• Simple interest is the rate at which we lend or borrow money. It is method for calculating interest charge on a loan.

• Principle is original amount of money ,the amount before any interest is applied.

Answer 2

↪Question :-

• Find the simple interest on a sum of Rs 8250 for 3 years at the rate of 8% per annum.

↪Solution :-

Given :

• Principal (P) = Rs 8250
• Rate (R) = 8 %
• Time (T) = 3 years

To Find :

• The simple interest (SI).

$\boxed {\tt {SI = \dfrac{P\times R \times T}{100}}}$

$\sf { :\implies{SI = \dfrac{P\times R \times T}{100}}} \\ \\ \sf { :\implies{SI =Rs \: ( \dfrac{8250\times 8\times 3}{100}) }} \\ \\ \sf { :\implies{SI =Rs \: \dfrac{198000}{100} }} \\ \\ \sf { :\implies{SI =Rs \:1980}}$

$\bf{\therefore{The\:simple\:interest\:is\:Rs\:1980.}}$

$\rule {307}{2}$