Question

Find the simple interest on Rs 10000 at the rate of 10 p.c.p.a for 1 year..​

Answer 1

Given :-

• Principal = Rs 10000.
• Rate = 10 p.c.p.a.
• Time = 1 year.

To find :-

• Simple interest.

Step-by-step explanation :-

Here, principal, rate and time are given to us. We are asked to find simple interest.

We know that :-

$\underline{ \boxed{\sf S I = \dfrac{Principal \times Rate \times Time}{100}}}$

Here,

• Principal = Rs 10000.
• Rate = 10 p.c.p.a.
• Time = 1 year.

----------------------

$\underline{\underline{\mathfrak{Putting\: the \:given\: values \:in \:formula,}}}$

$\tt SI = \dfrac{10000\times 10 \times 1}{100}$

Cutting off the zeroes,

$\tt SI = 1000 \times 1 \times 1$

Multiplying the numbers,

$\overline{\boxed{\tt{\bigstar \: \purple{SI =Rs \:1000}}} }$

----------------------

∴ Hence, Simple intrest on Rs 10000 at the rate of 10 p.c.p.a for 1 year is Rs 1000.

Answer 2

Given

Principal-₹10000

Rate-10%

n/time-1 year

Find

Simple interest

_________________

Formula

By using formula S. I=PRT/100

Solution

S. I=PRT/100

∴S. I=10000×10×1/100

∴S.I=100000/100

∴S.I=1000₹

Hence the simple interest is 1000₹

_________________________

More to learn

¡) Amount interest is compounded annually

=P[1+R/100]^n

P stands for principal

R stands for rate

n stands for time period..

¡¡) Amount when interest is compounded half yearly.

=[1+R/200]^2n

R/2 is half yearly rate

2n=number of half years