Question

Find the simple interest on Rs. 3600 for 2 years at 8℅ per annum. Also, find the amount
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Answer 1

Answer:

Given:

Principal = P = Rs. 3600

Time = T = 2 years

Rate = R = 8℅ per annum.

What to find?

We have to find the simple interest and amount on Rs. 3600 for 2 years at 8℅ per annum.

How to find?

To find the simple interest we use the formula, $SI=\frac{PRT}{100}$ and to amount we add the simple interest and the principal i.e., $A=P+SI$.

Solution:

First find the simple interest,

Using the formula and substituting the value of Principal (P), Time (T), Rate (R).

⇒ $SI = \frac{3600*2*8}{100}$

After canceling zeros from 3600 and 100,

⇒ SI = 36 × 2 × 8

⇒ SI = Rs. 576

∴ So, simple interest is Rs. 576.

Now find the amount,

$A=P+SI$

A = Rs. 3600 + Rs. 576

A = Rs. 4176

∴ So, the amount is Rs. 4176.

Answer 2

Answer:

• A = ₹4,176

• S.I = ₹576

Step-by-step explanation:

Given

• Principal = ₹3,600

• Time = 2 years

• Rate = 8 %

To Find

• S.I and Amount

Solution

• We know that S.I :-

• $\boxed{ \rm{S.I= \dfrac{PRT}{100} }}$

• $\boxed{ \rm{S.I= \dfrac{3,600 \times 8\times 2}{100} }}$

• $\boxed{ \rm{S.I= \dfrac{3,6 \cancel0 \cancel0 \times 8\times 2}{1 \cancel0 \cancel0} }}$

• $\tt S.I = 36 \times 8 \times 2$

• $\tt S.I = ₹576$

♤_________________♤

Now Let's Find Amount

• We know that :-

• S.I = A - P

• So, A = S.I + P

• A = 576 + 3,600

• A = ₹4,176