Question

find the simple interest on Rs 40000 for 5 years at 12% p.a​

Answer 1

Step-by-step explanation:

S.I= pnr÷100

given, Principal=40000, No of years=5,Rate of interest=12%

=> 40000×5×12÷100

=>Rupees 24000. therefore the S.I = 24000.

Answer 2

Given:

P = Rs. 40000

R = 5 years

T = 12% p.a​

To Find:

Find the simple interest

Solution:

We know that the formula to find the simple interest is as follows:

Simple Interest = (PRT) / 100

Here, we have

P = Rs. 40000

R = 5 years

T = 12% p.a​

By substituting these values in the formula, we get

SI = (40000 x 5 x 12) / 100

   = 400 x 60

   = Rs.24000

Hence, the simple interest on Rs 40000 for 5 years at 12% p.a​ will be Rs 24000.