Question

Find the simple interest on rs 4300 at 6% p.a for 3 years

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :

• Principal = Rs.4300

• Rate = 6%

• Time = 3years

$\begin{gathered}\begin{gathered}\begin{gathered} \\ \rule{200pt}{3pt} \end{gathered}\end{gathered}\end{gathered}$

To Find :

• Simple Interest = ?

$\begin{gathered}\begin{gathered}\begin{gathered} \\ \rule{200pt}{3pt} \end{gathered}\end{gathered} \end{gathered}</p><p>$

Solution :

$✭ {\underline{\pmb{\frak{ Formula \; Used \; :- }}}}$

• ${\underline{\boxed{\purple{\sf{ S.I = \dfrac{P \times R \times T}{100} }}}}}$

Where :

• ⊸ S.I = Simple Interest

• ⊸ P = Principal

• ⊸ R = Rate

• ⊸ T = Time

$\begin{gathered}\begin{gathered}\begin{gathered} \\ \qquad{\underline{\rule{150pt}{1pt}}} \end{gathered}\end{gathered}\end{gathered}$

$✭ {\underline{\pmb{\frak{ Calculating \; the \; Interest \; :- }}}}$

$\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered} \dashrightarrow \; \; \sf { S.I = \dfrac{P \times R \times T}{100} } \\ \end{gathered} \end{gathered} \end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered} \dashrightarrow \; \; \sf { S.I = \dfrac{4300\times 3\times 6}{100} } \\ \end{gathered} \end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered} \dashrightarrow \; \; \sf { S.I = \dfrac{ 43\cancel{00} \times 3 \times 6}{ \cancel{100}} } \\ \end{gathered} \end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered} \dashrightarrow \; \; \sf { S.I =43\times 3\times 6 } \\ \end{gathered} \end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered} \dashrightarrow \; \; \sf { S.I = 43 \times 3 \times 6 = \green{ \underline{774}}} \\ \end{gathered} \end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered} \dashrightarrow \; \; \sf { S.I = { \color{aqua} \underline{₹774}}} \\ \end{gathered} \end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered} {\qquad \; \; {\therefore \; {\underline{\boxed{\orange{\pmb{\frak{ Simple \; Interest = ₹ \; 774}}}}}}}} \\ \end{gathered} \end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \\ \qquad{\underline{\rule{150pt}{1pt}}} \end{gathered}\end{gathered}\end{gathered}$

~Therefore

$\begin{gathered} \begin{gathered} {\qquad \; \; {\therefore \;{\underline{\boxed{\green{\pmb{\frak{Simple \:Interest= ₹ \; 774}}}}}}}} \\\end{gathered} \end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered} \\{\underline{ \color{lime}{\rule{150000pt}{7pt}}}} \end{gathered}\end{gathered}\end{gathered}$