Question

find the simple interest on Rs. 5a²b² for 4ab years at 7b% per annum​

Answer 1

Answer:

simple interest =7a^3b^4

5

Solution:-

Given, Principal(p) =₹5a^2b^2

Years (n) =4ab

Rate. (r) =7b%

Simple interest=pnr

100

=5a^2b^2 ×4ab×7b

100

S.I =7a^3b^4

5

Step-by-step explanation:

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Answer 2

GIVEN :-

• Principal ( P ) = 5a²b².
• Time ( T ) = 4ab years.
• Rate ( R ) = 7b %.

TO FIND :-

• Simple Interest ( S.I ).

SOLUTION :-

$\\ : \implies \displaystyle \sf \: S.I = \dfrac{P \times R \times T}{100}$

$: \implies \displaystyle \sf \: S.I = \frac{5a ^{2}b ^{2} \times 7b \times 4ab}{100}$

$: \implies \displaystyle \sf \: S.I = \dfrac{35a ^{2} b ^{3} \times 4ab}{100}$

$: \implies \displaystyle \sf \: S.I = \frac{140a ^{3} b ^{4} }{100}$

$: \implies \displaystyle \sf \: S.I = \frac{14a ^{3}b ^{4} }{10}$

$: \implies \underline{ \boxed{\displaystyle \sf \: S.I = \frac{7a ^{3}b ^{4} }{5} }}$

Hence the required Simple Interest is Rs .$\displaystyle \sf \: \frac{7a ^{3}b ^{4} }{5}$