Question

Find the Simple Interest on Rs1000 in 3 years and 8 months at the rate 6% per annum.​

Answer 1

Answer:

Let the sum be Rs. z. Then,

S.I. = Rs. (504-z)

therefore (z x 5 x 4/100) = 504 - z

20z 50400 - 100z

120z = 50400

z = 420

Now P = 420, R = 10%, T = 5/2

S.I. = (420 x 10 x 100 x 2) = 105

Amount = Rs (420 +105) = 525

Answer 2

Solution

Given :

$\boxed{\sf \: Principle = ₹ \: 1000}$

$\boxed{\tt \: Rate = 6 \%}$

$\boxed{\bf \: Time = 3 \: years}$

$\red{\rule{190pt}{2pt}}$

Formula Used :-

$\tt \: Simple \: interest \: (S.I) = \frac{(P × R × T)}{100}$

$\blue{\rule{190pt}{2pt}}$

Calculation:

$\tt \: Simple \: interest \: = \dfrac{(1000 × 6 × 3)}{100}$

$\red{\boxed{\sf⇒ 180}}$

Hence, the simple interest is Rs. 180