Question

find the simple interest on Rupees 12800 at 9% per annum for 6 month also find the amount​

Answer 1

$\mathcal{ANSWER}$

$\rule{300}{1}$

$\times{P}\times{R}\times{T}$/100

$\rule{300}{1}$

$\implies$ $P=12800$

$\implies$ $Rate=9$%

$\implies$

$Time=6months=(2Years)$

$\rule{300}{1}$

Now

${P}\times{R}\times{T}/100$

${12800}\times{9}$%$\times{2}$

$\implies$ $\cancel\dfrac{100}{2}={50}$

$\implies$ ${12800}\times{9}\times{50}$

$\implies$ $=5760000$

$\rule{300}{1}$

Hence,The S.I = 5760000

$\rule{300}{1}$

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$\rule{300}{1}$

Answer 2

Question :

Find the simple interest on Rs 12800 at 9% per annum for 6 month, also find the amount.

Solution :

$\underline {\bold{Given:}}$

• Principal = Rs 12800
• Rate = 9%
• Time = 6 month = 1/2 year.

$\underline {\bold{To\:Find:}}$

• Simple interest .
• Amount .

$\rule {192}{2}$

$\boxed{\pink{Simple \: interest = \frac{Principal \times Rate \times Time}{100}}}$

$\implies Simple \: interest = \frac{Principal \times Rate \times Time}{100} \\ \implies Simple \: interest = Rs \: ( \frac{12800\times 9\times 1}{100 \times 2}) \\ \implies Simple \: interest = Rs \: (64 \times 9) \\ \implies Simple \: interest = Rs \: 576$

$\boxed{\green{\therefore{Simple \: interest = Rs \: 576}}}$

$\rule {192}{2}$

$\fbox {\blue {Amount =Principal+Simple\: interest}}$

$\implies Amount =Principal+Simple\: interest \\ \implies Amount = Rs \:(12800 + 576 )\\ \implies Amount =Rs \: 13376$

$\boxed{\green{\therefore{Amount = Rs \: 13376}}}$

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#BAL