Question

find the simple interest on rupees 500 for 3 year at 5% per annum explain plese ​

Answer 1

Answer:

follow me please

Step-by-step explanation:

S.I =500× 10× 3 ÷100 =150 answer

Answer 2

SimpleInterest=150rupees

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

Step−by−stepexplanation:

\begin{gathered}\green{\underline \bold{Given:}} \\ \tt: \implies Principal(p) = 500 \: rupees\\ \\ \tt: \implies Time(t) = 3 \: years \\ \\ \tt: \implies Rate\%(r)= 10\% \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Simple \: Interest(S.I) = ?\end{gathered}

Given:

:⟹Principal(p)=500rupees

:⟹Time(t)=3years

:⟹Rate%(r)=10%

ToFind:

:⟹SimpleInterest(S.I)=?

• According to given question :

\begin{gathered}\bold{As \: we \: know \: that} \\ \tt: \implies S.I= \frac{p \times r \times t}{100} \\ \\ \tt: \implies S.I= \frac{500 \times 10 \times 3}{100} \\ \\ \tt: \implies S.I = 5 \times 10 \times 3 \\ \\ \green{\tt:\implies S.I = 150 \: rupees} \\ \\ \bold{As \: we \: know \:that} \\ \tt: \implies A= p + S.I \\ \\ \tt: \implies A = 500 + 150 \\ \\ \green{\tt: \implies A = 650 \: rupees}\\ \purple{\tt{Some \: formula \: related \: to \: topic}} \\ \pink{\circ \: \tt A = p(1 + \frac{r}{100})^{t} } \\ \\ \pink{\circ \: \tt C.I= A - p }\end{gathered}

Asweknowthat

:⟹S.I=

100

p×r×t

:⟹S.I=

100

500×10×3

:⟹S.I=5×10×3

:⟹S.I=150rupees

Asweknowthat

:⟹A=p+S.I

:⟹A=500+150

:⟹A=650rupees

Someformularelatedtotopic

∘A=p(1+

100

r

)

t

∘C.I=A−p