Math, asked by smritigautam3291, 11 months ago

Find the simple interest on rupees 5000 at 8 p.c.p.a. for 219 days

Answers

Answered by subhashnidevi4878
40

Simple interest = Rs.240/-

Step-by-step explanation:

Given,

principal, p = 5000

Rate, r = 8 %

Time, t = 219 days = \frac{219}{365} = 0.6 years

We know that,

Simple interest = \frac{p\times r\times t}{100}

Simple interest = \frac{5000\times 8\times 0.6}{100}

Simple interest = \frac{24000}{100}

Simple interest = Rs.240/-

Answered by slicergiza
15

Simple interest would be rs 240

Step-by-step explanation:

Simple interest is,

I=\frac{P\times r\times t}{100}

Where,

P = principal,

r = rate of interest per period,

t = number of periods,

Here, P = 5000,

r = 8%,

Number of days = 219,

∵ 1 year = 365 days,

So, number of years, t = \frac{219}{365}

Hence, simple interest would be,

I=\frac{5000\times 8\times \frac{219}{365}}{100}

=\frac{50\times 8\times 219}{365}

=\frac{87600}{365}

= 240 rupees.

#Learn more:

The simple interst on a sum of money for 3 years at 12%p.a is rs 6750. What will be the compound interst on the same sum at the rate and for the same period compounded annually?

https://brainly.in/question/6854741

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