Math, asked by Anonymous, 4 months ago

find the simple interest on rupees 6000 at 4% p a fore 4 1 upon 2 years also find the amount to be paid at the end of the period​

Answers

Answered by ivananoj2007
0

Step-by-step explanation:

SI= (P×T×R)/100

Where,

P= Principal amount

T=Number of years

R=Rate of interest

Therefore,

=>SI= (6000×2×4)/100

=>SI= 60×8

=>SI= ₹480

Now, this means that the amount to be paid at the end of the period is,

P+SI=₹6000+₹480

=>₹6480

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