find the simple interest on rupees 6000 at 4% p a fore 4 1 upon 2 years also find the amount to be paid at the end of the period
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Step-by-step explanation:
SI= (P×T×R)/100
Where,
P= Principal amount
T=Number of years
R=Rate of interest
Therefore,
=>SI= (6000×2×4)/100
=>SI= 60×8
=>SI= ₹480
Now, this means that the amount to be paid at the end of the period is,
P+SI=₹6000+₹480
=>₹6480
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