find the simple interest on rupees 8000 at 4percent per annum for 2 years
Answers
Answered by
0
Step-by-step explanation:
Compound interest (C.I)=P[(1+
100
r
)
t
−1]
P= Principal r= rate, t= time
⇒ C.I. =8000[(1+
100
5
)
2
−1]
=8000[
1000
25
+
100
10
]=8000[
10000
25+1000
]
⇒C.I=
10
8
[1025]=14.820.
solution
Answered by
3
Answer:
P[(1+
100
r
)
t
−1]
P= Principal r= rate, t= time
⇒ C.I. =8000[(1+
100
5
)
2
−1]
=8000[
1000
25
+
100
10
]=8000[
10000
25+1000
]
⇒C.I=
10
8
[1025]=14.820.
Step-by-step explanation:
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