Question

Find the simple interest payable on a loan of ₹300000 at12% per annum for 3 years.

Answer 1

Answer:

Given,

P=₹300000

R=12%

T=3

S.I=?

S.I=(P×R×T)/100

S.I=(300000×12×3)/100

S.I=3000×12×3

S.I=108,000

Step-by-step explanation:

please make me as brainliest

Answer 2

Information provided with us:

➪ Principal

$\implies \sf \:300000\: Rs$

➪Time

$\implies \sf \: 3 \: years$

➪ Rate of Interest

$\sf\implies \: 12 \: \% \: per \: annum$

What we have to calculate༄

➪The required simple interest

✰Formula used ༄

$\clubsuit \: \rm \:Simple \: Interest :$

$\longrightarrow\bigstar \: \: \sf\boxed{\bold{\orange{ \bigg(\dfrac{P \times R \times T}{100}\bigg)}}}\: \: \: \bigstar$

✰Where ༄

• ➡ P = Principle

• ➡ R = Rate of Interest

• ➡ T = Time

✰Now ༄

• ➡ Substitute the given values in above formula and solve

$\longrightarrow\bigstar \: \: \sf\boxed{\bold{\green{ \bigg(\dfrac{300000\times 12 \times 3}{100}\bigg)}}}\: \: \: \bigstar$

$\longrightarrow\bigstar \: \: \sf\boxed{\bold{\red{ \bigg(\dfrac{10800000}{100}\bigg)}}}\: \: \: \bigstar$

$\longrightarrow\bigstar \: \: \sf\boxed{\bold{\blue{108,000 \:Rs }}}\: \: \: \bigstar$

✰Therefore༄

$\rm \therefore \: Thus \: required \: simple \: interest\:is$

$\implies\bigstar \: \: \sf\boxed{\bold{\gray{108,000 \:Rs }}}\: \: \: \bigstar$