Question

find the simple interest principal is equal to 8000 rate 8% time 3 years also find the amount

Answer 1

SI= PRN/100

= (8000×8×3)/100

=80×8×3

=1920

TOTAL AMOUNT = 8000+1920= 9920

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=1920\:rupees}}}$

$\green{\therefore{\text{Amount=9920\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 3\:years} \\ \\ : \implies \text{Principal(p) = 8000\:rupees} \\ \\ : \implies \text{Rate(r) = 8\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}\\\\ :\implies \text{Amount=?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{8000 \times 8\times3}{100} \\ \\ : \implies S.I = \frac{8000 \times24}{100 } \\ \\ \green{ : \implies \text{S.I= 1920\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =1920\: rupees}} \\ \\ :\implies Amount=S.I+principal\\\\ \green{:\implies\text{Amount=1920+8000=9920\:rupees}} \\\\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$