Question

find the simple interest when principal is equal to 1200 at 12% p.a with no time

Answer 1

GiVen:

• P = 1200

• R = 12%

• T = 3 years.

AnSwer:

★ According to the question,

$\implies{ \boxed{ \boxed{ \sf {SI = \dfrac{P \times R \times T}{100}}}}} \\ = \frac{1200 \times 12 \times 3}{100} \\ = 43200/100 \\ = 432.</p><p>$

We know that Amount = Principal + Interest

                                      = 1200 + 432

                                      = 1632.

The amount to be paid 1632 rupees.

Answer 2

$\sf{\underline{\huge{\boxed{\purple{\mathfrak{Question}}}}}}$

• find the simple interest when principal is equal to 1200 at 12% p.a in 3 years .

$\sf{\underline{\huge{\boxed{\purple{\mathfrak{Solution}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• principle = Rs. 1200
• rate = 12% per annum
• time = 3years

$\sf{\bold{\blue{\underline{\underline{To\:find}}}}}$

• simple interest = ????

$\sf{\bold{\pink{\underline{\underline{Explanation}}}}}$

$\sf{\bold{\red{\boxed{Simple \: interest = \dfrac{PRT}{100}}}}}$

$\\ \sf\bold\implies Simple\: Interest = \dfrac{1200\times 12 \times 3}{100}$

$\\ \sf\bold\implies Simple\: Interest = \dfrac{12 \cancel{00}\times 12 \times 3}{\cancel{100}}$

$\\ \sf\bold\implies Simple\: Interest = 144 \times 3$

$\\ \sf\bold\implies Simple\: Interest = Rs. 432$

$\sf{\underline{\boxed{\purple{\mathbb{S.I. = \:Rs. 432 }}}}}$

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