Question

Find the simple interest when Principal is Rs. 4500 , rate of interest is 4%per annum and time is 6 months. *
Rs. 90
Rs. 100
Rs. 110​

Answer 1

➤ Given :-

Principle :- ₹4500

Rate of interest :- 4%

Time :- 6 months

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➤ To Find :-

The simple interest of the given sum.

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★ How to do :-

Here, we are given with the principle amount, the rate of interest and the time taken to give back money. We are asked to find the simple interest of the given sum. So, we have an appropriate formula to calculate the simple interest. So, we can easily find the value of the simple interest. We know that always the time period given to return back the money should always be in the form of years. So, first let's find the time in years and then solve the answer.

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➤ Solution :-

Time (in years) :-

${\tt \leadsto 6 \: \: months}$

Write it in the form of fraction.

${\tt \leadsto \cancel \dfrac{6}{12} = \dfrac{1}{2} \: \: years}$

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Now, let's find the simple interest of this problem.

Simple Interest :-

${\tt \leadsto \underline{\boxed{\tt \dfrac{P \times R \times T}{100}}}}$

Substitute the given values.

${\tt \leadsto \dfrac{4500 \times 4 \times 1}{100 \times 2}}$

Cancel the zeros in numerator and denominator.

${\tt \leadsto \dfrac{45 \cancel{00} \times 4 \times 1}{1 \cancel{00} \times 2} = \dfrac{45 \times 4 \times 1}{1 \times 2}}$

Write the numbers in numerator and denominator in lowest form by cancellation method.

${\tt \leadsto \dfrac{45 \times \cancel{4} \times 1}{1 \times \cancel{2}} = \dfrac{45 \times 4 \times 1}{1 \times 1}}$

Multiply the remaining numbers in numerator and denominator.

${\tt \leadsto \cancel \dfrac{180}{1} = \pink{\underline{\boxed{\tt Rs \: \: 180}}}}$

$\Huge\therefore$ The simple interest of the given sum is ₹180.

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$\dashrightarrow$ Some related formulas :-

$\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Principle :- \dfrac{SI \times 100}{R \times T}} \\ \\\bigstar \: \sf{Rate \: of \: Interest :- \dfrac{SI \times 100}{P \times T}} \\ \\ \bigstar \: \sf{Time :- \dfrac{SI \times 100}{P \times R}}\end{array}}$