Math, asked by krsheamanth, 1 month ago

find the simple interset of the amout rs 12500 at the rate of 12 5% of 3years​

Answers

Answered by sps12811
1

Answer:

Here, Principal (P) = Rs.12,500, Time (T) = 3 years, Rate of interest (R) = 12% p.a.

Simple interest for Fabina = \frac{P\times R\times T}{100}=\frac{12500\times12\times3}{100}=\ Rs.\ 4,500

100

P×R×T

=

100

12500×12×3

= Rs. 4,500

Amount for Radha, P = Rs. 12,500, R = 10% and n = 3 years

Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+

100

R

)

n

= 12500\left(1+\frac{10}{100}\right)^3=12500\left(1+\frac{1}{10}\right)^312500(1+

100

10

)

3

=12500(1+

10

1

)

3

= 12500\left(\frac{11}{10}\right)^2=12500\times\frac{11}{10}\times\frac{11}{10}\times\frac{11}{10}12500(

10

11

)

2

=12500×

10

11

×

10

11

×

10

11

= Rs. 16,637.50

\therefore∴ C.I. for Radha = A – P

= Rs. 16,637.50 – Rs. 12,500 = Rs. 4,137.50

Here, Fabina pays more interest

= Rs. 4,500 – Rs. 4,137.50 = Rs. 362.50

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