Math, asked by rohan74236, 1 year ago

find the simple interset on 10000rs. for 2 yr. at 12%p.a also find amount​

Answers

Answered by DevdattAgrawal
0

Answer:

$12400.00

Step-by-step explanation:

You want to calculate the interest on rs.10000 at 12% interest per year after 2 year(s).

The formula we'll use for this is the simple interest formula, or:

Where:

P is the principal amount, rs.10000.00.

r is the interest rate, 12% per year, or in decimal form, 12/100=0.12.

t is the time involved, 2....year(s) time periods.

So, t is 2....year time periods.

To find the simple interest, we multiply 10000 × 0.12 × 2 to get that:

The interest is: rs.2400.00

Usually now, the interest is added onto the principal to figure some new amount after 2 year(s),  

or 10000.00 + 2400.00 = 12400.00. For example:

If you borrowed the rs.10000.00, you would now owe rs.12400.00

If you loaned someone rs.10000.00, you would now be due rs.12400.00

If owned something, like a rs.10000.00 bond, it would be worth rs.12400.00 now.

Answered by Sahastranshudinkar
0

10000×12×2/100=2400this is simple interest for 2 years

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