Question

find the simple intrest and amount for rs12000for one and half years at 6% per annun​

Answer 1

Answer :-

• Simple interest = ₹ 1080
• Amount = ₹ 13080

Step-by-step explanation :-

Given:

• Principal (P) = ₹ 12000
• Time (T) = 1.5 years
• Rate of interest (R) = 6% p.a

To find:

Simple interest = ?

Amount = ?

Solution:

S.I = PTR ÷ 100

⇒ S.I = (12000 × 1.5 × 6) ÷ 100

⇒ S.I = 108000 ÷ 100

⇒ S.I = 1080

∴ Simple interest = ₹ 1080

For finding the amount:

Amount = Principal + Simple interest

⇒ Amount = 12000 + 1080

⇒ Amount = ₹ 13080

∴ Amount = ₹ 13080

Answer 2

Given :-

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• Principal = ₹12000

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• Time = 1.5 years

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• Rate = 6% p.a

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To find :-

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• Simple intrest

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• Amount

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Solution :-

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★ Here we have Principle , Time, and Rate so to find the simple intrest and amount we have to use the formula .

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Simple intrest:-

$\qquad \sf{ \implies \: Simple \: intrest \: = \: \dfrac{principle \: \times \: time \: \times \: rate}{100 }}$

$\qquad \sf{ \implies \: Simple \: intrest \: = \: \dfrac{12000 \: \times \: 1.5 \: \times \: 6}{100 }}$

$\qquad \sf{ \implies \: Simple \: intrest \: = \: \dfrac{108000}{100 }}$

$\qquad \sf{ \implies \: Simple \: intrest \: = \: 1080}$

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Therefore the simple intrest is of ₹ 1080 .

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Amount :-

$\qquad \sf{ \implies \: Amount \: = \: principle \: + \: simple \: intrest}$

$\qquad \sf{ \implies \: Amount \: = \: 12000 \: + \: 1080}$

$\qquad \sf{ \implies \: Amount \: = \: 13080}$

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Therefore the amount is of ₹ 13080 .