Question

find the simple Intrest and amount if p=150 r=5% per annum and t=4years​

Answer 1

Given:

• Principal = Rs. 150
• Rate = 5 %
• Time = 4 years

What To Find:

We have to find the

• Simple Interest
• Amount

Formula Needed:

$\bf 1. \: SI = \dfrac{P \times R \times T}{100}$

$\bf 2. \: A = P + SI$

Abbreviation Used:

• SI = Simple Interest
• A = Amount
• P = Principal
• R = Rate
• T = Time

Solution:

• Finding the SI.

Using the formula,

$\sf \implies SI = \dfrac{P \times R \times T}{100}$

Substitute the values,

$\sf \implies SI = \dfrac{150 \times 5 \times 4}{100}$

Multiply 5 and 4,

$\sf \implies SI = \dfrac{150 \times 20}{100}$

Cancel the zeros,

$\sf \implies SI = 15 \times 2$

Multiply 15 and 2,

$\sf \implies SI = Rs. \: 30$

• Finding the A.

Using the formula,

$\sf \implies A = P + SI$

Substitute the values,

$\sf \implies A = 150 + 30$

Add the values,

$\sf \implies A = Rs. \: 180$

Final Answer:

Therefore, the SI is Rs. 30 and A is Rs. 180.

Answer 2

Question :-

• Find Simple Interest and Amount , if Principal is ₹ 150 , Rate is 5 % and Time is 4 years .

Answer :-

• Simple Interest is Rs. 30
• Amount is Rs. 180

$\rule {180pt} {2pt}$

Given :-

• Principal = Rs. 150
• Rate of Interest = 5 %
• Time Period = 4 years

To Find :-

• Simple Interest = ?
• Amount = ?

Solution :-

As per the provided information in the given question, we have been given that the Principal is Rs. 150 , Rate of Interest is given 5 % , Time Period is 4 years . And, we have been asked nto calculate the Simple Interest and Amount .

Formula Required :-

$\bigstar \: \: \: \boxed { \sf \pink { \: Simple \: Interest \: = \: \frac{P \times R \times T}{100} \: }}$

$\bigstar \: \: \: \boxed{ \sf \pink { \: Amount \: = \: P \: + \: S.I \: }}$

Where ,

• P denotes to Principal
• R denotes to Rate of Interest
• T denotes to Time Period
• S.I denotes to Simple Interest

Now, first we will find Simple Interest . By substituting the values in the First Formula :-

$\dag \: \: \sf { Simple \: Interest \: = \: \dfrac{P \times R \times T}{100}}$

$\longmapsto \: \: \sf{Simple \: lnterest \: = \: \dfrac{150 \times 5 \times 4}{100} }$

$\longmapsto \: \: \sf{Simple \: lnterest \: = \: \dfrac{15 \cancel{0} \times 5 \times 4}{10 \cancel{0}} }$

$\longmapsto \: \: \sf{Simple \: lnterest \: = \: \dfrac{15 \times 5 \times 4}{10} }$

$\longmapsto \: \: \sf{Simple \: lnterest \: = \: \dfrac{300}{10} }$

$\longmapsto \: \: \textbf{ \textsf{Simple \: lnterest \: = \: 30 }}$

Now, here we will find Amount . By substituting the values in the Second Formula :-

$\dag \: \: { \sf { \: Amount \: = \: P \: + \: S.I \: }}$

$\longmapsto \: \: \sf {Amount \: = \: 150\: + \: 30}$

$\longmapsto \: \: \textbf{ \textsf {Amount = 180 }}$

Hence :-

• Simple Interest = Rs. 30
• Amount = Rs. 180

$\rule {180pt} {4pt}$

Learn More :-

$\bigstar \: \: \: \boxed {\sf { \: \: Principal \: = \: \dfrac {Simple \: Interest \: \times \: 100}{Rate \: \times \: Time \: \: }}}$

$\bigstar \: \: \: \boxed {\sf { \: \: Rate \: = \: \dfrac {Simple \: Interest \: \times \: 100}{Principal \: \times \: Time \: \: }}}$

$\bigstar \: \: \: \boxed {\sf { \: \: Time \: = \: \dfrac {Simple \: Interest \: \times \: 100}{Principal \: \times \: Rate \: \: }}}$