find the simplest form of 561÷748 by HCF
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hcf of 561 and 748 = 187
561/748 = 3×11×17 / (2×2×11×17)
= 3/4 = 0.75
561/748 = 3×11×17 / (2×2×11×17)
= 3/4 = 0.75
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2
561 )748( 1
561
_____
187 )561( 3
561
_____
0
561
_____
187 )561( 3
561
_____
0
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