Find the simplest rationalising factor of √5+√3+2.
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(2+3+5)(2+3−5)=(2+3)2−(5)2
=4+3+43−5=7+43−5
=2+43=2(1+23)
Now, conjugate of factor 1+23 is 1−23
=(1+23)(1−23)=12−(23)2
=1−4×3=−11
∴(2+3+5)(2+
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