Find the sine of the angle between the vectors 3i+ j− 2k and i+ k.
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a =3i +j+2k
b=2i-2j+4k
axb = i(4+4)-j (12-4)+k (-6 -2)
=8i -8j-8k
|axb| = (64+64+64)1/2
= (192)1/2
|a| = (9+1+4)1/2 =141/2
|b|= (4+4+16)1/2 =241/2
SinQ =|axb|/|a| |b|
= (192)1/2 /(14)1/2 (24)1/2
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