Question

find the six terms of ap where a=5,d=4

Answer 1

Heya mate,

Your solution is in the attachment.
Refer to it.

#KEVIN
Hope it will help you...

Answer 2

The answer is given below :

We know that the nth term of an AP is

= tn = a + (n - 1)d,

where a is the first term of the AP and d is the common difference for the AP.

In this problem, the first term (a) = 5 and the common difference (d) = 4.

So, the 2nd term
= 5 + (2 - 1)×4
= 5 + 4
= 9,

the 3rd term
= 5 + (3 - 1)×4
= 5 + 8
= 13,

the 4th term
= 5 + (4 - 1)×4
= 5 + 12
= 17,

the 5th term
= 5 + (5 - 1)×4
= 5 + 16
= 21,

the 6th term
= 5 + (6 - 1)×4
= 5 + 20
= 25

So, the AP is written as
5, 9, 13, 17, 21, 25, ...

EASY METHOD :

For an increasing AP, the next term is always the sum of the previous term and the common difference.

So, the AP be
5, 5+4, (5+4)+4, (5+4+4)+4, (5+4+4+4)+4, (5+4+4+4+4)+4, ...

⇒ 5, 9, 13, 17, 21, 25, ...

Thank you for your question.