Question

find the sixth term of the sequence whose first term is 1 and (n + 1)th term can be obtained by adding n to the nth term.

Answer 1

See tge attachment for answer .

Answer 2

it is given that first term is 1 ,
so, $a_1=1$

relation is given,
$a_{(n+1)}=n+a_n$

$a_{(1+1)}=a_2=1+a_1=1+1=2$

$a_{(2+1)}=a_3=2+a_2=2+2=4$

$a_{(3+1)}=a_4=3+a_3=7$

$a_{(4+1)}=a_5=4+a_4=11$

$a_{(5+1)}=a_6=5+a_5=16$

hence, $a_6=16$