Find the size, nature and pisition of image formed when an object of size 1cm is placed at a distance of 15cm from a concave mirror of focal length 10cm.
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Answer:Nature : real image Position of image : 30cm in front of lens or -30cm Height of image : -2cm(the image is inverted)
Explanation:Explanation given in the attachment.
Hope it helps.
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Answer:
GIVEN :
H = 1CM
U = -15CM ( you is generally considered as negative)
F = -10 ( focal lenght of concave mirror is negative)
Using mirror formula,
1/f = 1/u + 1/v
1/-10 = 1/ -15 + 1/v
1/v = 1/-10 - 1/-15
1/v = 1/-10 + 1/15
1/v = -15 +10 / 150 (taking l.c.m.)
1/v = -5/ 150
1/v = -30cm
Using magnification formula,
-v/u = m
-(-30)/-15 = m
-2 = m
Image is real and inverted (-) , enlarge (m<1)
h'/h = m
h'/1 = -2
h' = 2
image is twice the size of object..
HOPE IT HELPS YOU...
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