Question

find the size, nature and position of image formed by a concave mirror, when an object of size 1cm is placed at a distance of 15cm. give focal length of mirror is 10cm

Answer 1

hiii friend
here is your answer
the mirror is concave.
so,
f =10cm
u= 15cm
v=? ( to find)
$\frac{1}{f} = \frac{1}{u} + \frac{1}{v } \\ \frac{1}{10} = \frac{1}{ - 15} + \frac{1}{v} \\ \frac{1}{10} + \frac{1}{15} = \frac{1}{v} \\ \frac{3 + 2}{30} = \frac{1}{v} \\ \frac{5}{30} = \frac{1}{v} \\ v = 6 \: cm$

so,
as the image is near the mirror
nature = real,inverted
size = diminished
position = detween the pole and focus.


glad to help you
hope it helps
thank you

Answer 2

$\textbf{Answer is in Attachment !}$