Question

find the size nature and position of image formed when an object of size 1 cm is placed at a distance of 15 cm from a concave mirror of focal length 10 cm

Answer 1

Answer:

Explanation:

u=(-15) cm

f= (-10)cm

by mirror formula ,

1/f=1/v+1/u

1/f-1/u=1/v

1/(-10)-1/(-15)=1/v

-1/10+1/15=1/v

(-3+2)/30=1/v

-1/30=1/v

∴ v=(-30)

magnification=-v/u=height of image/ height of object

-(-30)/-15=height of image/1

-2=height of image/1

-2= height of image/size of image.

it is real in nature and beyond c