Question

find the size nature and position of image formed when an object of size 1 cm is placed at a distance of 15 cm from a concave mirror of focal length 10cm​

Answer 1

Answer:

The given mirror is a concave mirror thus sign convention it's focal length will be negative.

This here f = -10 cm u = -15cm h(height of object) = 1cm

we have to find size , nature , position of image formed .

Thus using mirror equation :-1/f = 1/u+1/v =>1/v = 1/f-1/u => 1/v = -1/10+1/15 => 1/v = -1/30 => v = -30 { thus image will be formed beyond center Now magnification m = -(v/u) = h'/h m = -(-30/-15) => m = -2 HENCE the image formed will be real and inverted and magnified.

Now m = h'/h 2 = h'/1 => h' = 2cm hence the size of the image will be doubled