Question

find the size nature and position of image formed when an object of size 1 cm is placed at a distance of 15 cm from a concave mirror of a focal length 10cm

Answer 1

object distance=15 cm
focal length = 10 cm
for a concave mirror
1/f=1/u+1/v
1/10+1/15= 1/v
3+2/30
v= 6 cm
diminished
inverted
real

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\fcolorbox{black}{aqua}{Solution:-}$

✒ ᴀɴsᴡᴇʀ:-

⛄ ★ ɪᴍᴀɢᴇ ᴅɪsᴛᴀɴᴄᴇ, ᴠ = -30 ᴄᴍ

★ sɪᴢᴇ ᴏғ ᴛʜᴇ ɪᴍᴀɢᴇ = -2 ᴄᴍ

★ ɴᴀᴛᴜʀᴇ ᴏғ ᴛʜᴇ ɪᴍᴀɢᴇ = ʀᴇᴀʟ & ɪɴᴠᴇʀᴛᴇᴅ

✒ ᴇxᴘʟᴀɴᴀᴛɪᴏɴ:-

⛄ ɢɪᴠᴇɴ ᴛʜᴀᴛ,

★ ᴜ = -15 ᴄᴍ,

★ ғ = -10 ᴄᴍ,

★ ʜ = 1 ᴄᴍ

ғʀᴏᴍ ᴛʜᴇ ᴍɪʀʀᴏʀ ғᴏʀᴍᴜʟᴀ, ᴡᴇ ʜᴀᴠᴇ,

1/ғ = 1/ᴜ + 1/ᴠ

⇒1/ᴠ = 1/ғ - 1/ᴜ

⇒1/ᴠ = 1/-10 - 1/-15

⇒ᴠ = -30 ᴄᴍ

∴ ᴛʜᴇ ɪᴍᴀɢᴇ ɪs ғᴏʀᴍᴇᴅ ᴀᴛ ᴀ ᴅɪsᴛᴀɴᴄᴇ ᴏғ 30 ᴄᴍ ɪɴ ғʀᴏɴᴛ ᴏғ ᴛʜᴇ ᴍɪʀʀᴏʀ ғʀᴏᴍ ᴛʜᴇ ᴘᴏʟᴇ.

ɴᴏᴡ,

ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,

ᴍ = ʜ'/ʜ = -ᴠ/ᴜ

⇒ʜ' = -1 × -30/-15

⇒ʜ' = -2 ᴄᴍ

∴ ᴛʜᴇ ɪᴍᴀɢᴇ sɪᴢᴇ ɪs ᴏғ 2 ᴄᴍ ᴀɴᴅ ɪs ʀᴇᴀʟ ᴀɴᴅ ɪɴᴠᴇʀᴛᴇᴅ.

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